5x^2+(3/5)x+(12/25)=0

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Solution for 5x^2+(3/5)x+(12/25)=0 equation:


x in (-oo:+oo)

5*x^2+(3/5)*x+12/25 = 0

5*x^2+3/5*x+12/25 = 0

DELTA = (3/5)^2-(12/25*4*5)

DELTA = -231/25

DELTA < 0

x belongs to the empty set

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